NGC 210
| NGC 210 | |
|---|---|
| File:N210s.jpg NGC 210 by Adam Block/Mount Lemmon SkyCenter | |
| Observation data (J2000.0 epoch) | |
| Constellation | Cetus[1] |
| Right ascension | 00h 40m 35.0s |
| Declination | −13° 52′ 20″ |
| Redshift | 0.005457 |
| Heliocentric radial velocity | 1636 km/s (1016.5 mi/s)[2] |
| Distance | 20.5 ± 1.5 Mpc (67 ± 5 Mly.)[3] |
| Apparent magnitude (V) | 11 |
| Characteristics | |
| Type | SAB(s)b[2] or Sb D[4] |
| Apparent size (V) | 5.012' x 3.09' [5] |
| Other designations | |
| MCG -02-02-081, 2MASX J00403502-1352220, 2MASXi J0040349-135221, IRAS 00380-1408, IRAS F00380-1408, AKARI J0040346-135214, CGS 126, 6dF J0040350-135222, LDCE 0041, HDCE 0030, USGC S024, AGC 400333, GSC 5271 00477, HIPASS J0040-13, PGC 2437 | |
NGC 210 is a barred spiral galaxy located roughly 67 million light-years from the Solar System in the constellation Cetus. It was discovered on October 3, 1785 by William Herschel and later added to the New General Catalogue.
Physical properties
[edit | edit source]It appears to be in loose association with NGC 157 and NGC 131. It is noted for its peculiar arms, which appear to be in the process of becoming a ring galaxy. They also have several apparently dense regions throughout them. The inner part of the galaxy appears to be lenticular, with a dust lane in it. The nucleus of the galaxy appears much brighter than the rest of it, suggesting an active galactic nucleus.
Satellites
[edit | edit source]In the image at the right, 2MASX J00403079-1353088 is the edge-on galaxy directly below the brightest star in the image. It is possibly a satellite of NGC 210, but without a redshift to determine its distance, it could just as possibly be completely unrelated to NGC 210.
Supernova
[edit | edit source]SN 1954R (type unknown, mag. 15.9) was discovered by Fritz Zwicky on 7 September 1954 in the outer edge of NGC 210's left arm, and is likely associated with the galaxy.[6][7][8]
Gallery
[edit | edit source]-
2MASS Near-infrared image of NGC 210
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PanSTARRS image of NGC 210
References
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- ^ An object's distance from Earth can be determined using Hubble's law: v=Ho is Hubble's constant (70±5 (km/s)/Mpc). The relative uncertainty Δd/d divided by the distance is equal to the sum of the relative uncertainties of the velocity and v=Ho
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External links
[edit | edit source]- Error creating thumbnail: File missing Media related to Lua error in Module:Commons_link at line 62: attempt to index field 'wikibase' (a nil value). at Wikimedia Commons
