Vanadium(V) chloride
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| Names | |
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| Other names
vanadium pentachloride
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| Identifiers | |
3D model (JSmol)
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PubChem CID
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CompTox Dashboard (EPA)
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| Properties | |
| Cl10V2 | |
| Molar mass | 456.38 g·mol−1 |
| Appearance | black solid |
| Density | 2.69 g/cm3 |
| Melting point | −10 °C (14 °F; 263 K) (decomposes) |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Vanadium(V) chloride is the inorganic compound with the formula VCl5. It is a black diamagnetic solid. The molecules adopt a bioctahedral structure similar to that of niobium(V) chloride.[1]
Preparation and reactions
[edit | edit source]Chlorine cannot oxidise vanadium(IV); chlorination of vanadium metal will yield only vanadium(IV) chloride. Vanadium(V) chloride is instead prepared from vanadium pentafluoride with excess boron trichloride as a chlorinating agent:
- 2 VF5 + 10 BCl3 → [VCl5]2 + 10 BF2Cl
It is unstable at room temperature, releasing gaseous chlorine and giving vanadium(IV) chloride:
- [VCl5]2 → 2 VCl4 + Cl2
In contrast, the heavier analogues NbCl5 and TaCl5 are stable and not particularly oxidizing.
References
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