Univalent function

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In mathematics, in the branch of complex analysis, a holomorphic function on an open subset of the complex plane is called univalent if it is injective.[1][2]

Examples

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The function f:z2z+z2 is univalent in the open unit disc, as f(z)=f(w) implies that f(z)f(w)=(zw)(z+w+2)=0. As the second factor is non-zero in the open unit disc, z=w so f is injective.

Basic properties

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One can prove that if G and Ω are two open connected sets in the complex plane, and

f:GΩ

is a univalent function such that f(G)=Ω (that is, f is surjective), then the derivative of f is never zero, f is invertible, and its inverse f1 is also holomorphic. More, one has by the chain rule

(f1)(f(z))=1f(z)

for all z in G.

Comparison with real functions

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For real analytic functions, unlike for complex analytic (that is, holomorphic) functions, these statements fail to hold. For example, consider the function

f:(1,1)(1,1)

given by f(x)=x3. This function is clearly injective, but its derivative is 0 at x=0, and its inverse is not analytic, or even differentiable, on the whole interval (1,1). Consequently, if we enlarge the domain to an open subset G of the complex plane, it must fail to be injective; and this is the case, since (for example) f(εω)=f(ε) (where ω is a primitive cube root of unity and ε is a positive real number smaller than the radius of G as a neighbourhood of 0).

See also

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  1. ^ (Conway 1995, p. 32, chapter 14: Conformal equivalence for simply connected regions, Definition 1.12: "A function on an open set is univalent if it is analytic and one-to-one.")
  2. ^ (Nehari 1975)

References

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