Samarium tetraboride

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Samarium tetraboride
File:YB4structure.jpg
Names
IUPAC name
Samarium tetraboride
Identifiers
3D model (JSmol)
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Properties
SmB4
Molar mass 193.60 g/mol
Density 6.1 g/cm3
Melting point 2,400 °C (4,350 °F; 2,670 K)
Related compounds
Related compounds
Samarium hexaboride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Samarium tetraboride is a binary inorganic compound of samarium and boron with the formula SmB4. It forms black crystals.

Preparation

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Samarium tetraboride can be prepared from directly reacting samarium and boron at 2400 °C:

Sm + 4B → SmB4

Physical properties

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Samarium tetraboride forms crystals of the orthorhombic crystal system, space group P4/mbm, cell parameters a = 0.7174 nm, c = 0.40696 nm, Z = 4, and a structure like thorium tetraboride.[1][2][3][4][5]

The compound is formed by a peritectic reaction at a temperature of 2400 °C.[1]

At temperatures of 25 K and 7 K, magnetic transitions occur in the compound.[6]

References

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