Samarium tetraboride
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| Names | |
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| IUPAC name
Samarium tetraboride
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| Identifiers | |
3D model (JSmol)
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CompTox Dashboard (EPA)
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| Properties | |
| SmB4 | |
| Molar mass | 193.60 g/mol |
| Density | 6.1 g/cm3 |
| Melting point | 2,400 °C (4,350 °F; 2,670 K) |
| Related compounds | |
Related compounds
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Samarium hexaboride |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Samarium tetraboride is a binary inorganic compound of samarium and boron with the formula SmB4. It forms black crystals.
Preparation
[edit | edit source]Samarium tetraboride can be prepared from directly reacting samarium and boron at 2400 °C:
- Sm + 4B → SmB4
Physical properties
[edit | edit source]Samarium tetraboride forms crystals of the orthorhombic crystal system, space group P4/mbm, cell parameters a = 0.7174 nm, c = 0.40696 nm, Z = 4, and a structure like thorium tetraboride.[1][2][3][4][5]
The compound is formed by a peritectic reaction at a temperature of 2400 °C.[1]
At temperatures of 25 K and 7 K, magnetic transitions occur in the compound.[6]
References
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