Halex process
In chemistry, the Halex process is used to convert aromatic chlorides to the corresponding aromatic fluorides. The process entails Halide exchange, hence the name.[1] The reaction conditions call for hot (150–250 °C) solutions of the aryl chloride and anhydrous potassium fluoride. Typical solvents are dimethylsulfoxide, dimethylformamide, and sulfolane. Potassium chloride is generated in the process. The reaction is mainly applied to nitro-substituted aryl chlorides. Sometimes more soluble fluorides, such as caesium fluoride and TBAF are used.[2]
The following reactions are practiced commercially in this manner:[3]
- 2-nitrochlorobenzene → 2-fluoronitrobenzene
- 4-nitrochlorobenzene → 1-fluoro-4-nitrobenzene
- 1,2-dichloronitrobenzene → 1-chloro-2-fluoro-5-nitrobenzene
- 1,4-dichloronitrobenzene → 1-chloro-4-fluoro-3-nitrobenzene
- 1-chloro-2,4-dinitrobenzene → 1-fluoro-2,4-dinitrobenzene
- 5-chloro-2-nitrobenzotrifluoride → 5-fluoro-2-nitrobenzotrifluoride
- 1,3-dichloro-4-nitrobenzene → 1,3-difluoro-4-nitrobenzene
- 2,6-dichlorobenzonitrile → 2,6-difluorobenzonitrile
The nitro groups in the above compounds can be reduced to give the corresponding aniline. For example, selective hydrogenation of 4-fluoronitrobenzene gives 4-fluoroaniline. Thus, the Halex method provides access to a host of fluoroanilines.
For producing aryl fluorides, the Halex process is complementary to the Balz-Schiemann reaction and its variants.
References
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- ^ ACS Green Chemistry Halex Reaction
- ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value)..