Ext functor

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In mathematics, the Ext functors are the derived functors of the Hom functor. Along with the Tor functor, Ext is one of the core concepts of homological algebra, in which ideas from algebraic topology are used to define invariants of algebraic structures. The cohomology of groups, Lie algebras, and associative algebras can all be defined in terms of Ext. The name comes from the fact that the first Ext group Ext1 classifies extensions of one module by another.

In the special case of abelian groups, Ext was introduced by Reinhold Baer in 1934.[1] It was named by Samuel Eilenberg and Saunders MacLane in 1942,[2] and applied to topology (the universal coefficient theorem for cohomology). For modules over any ring, Ext was defined by Henri Cartan and Eilenberg in 1956.[3]

Definition

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Let R be a ring and let R-Mod be the category of modules over R. (One can take this to mean either left R-modules or right R-modules.) For a fixed R-module A, let T(B)=HomR(A,B) for B in R-Mod. (Here HomR(A,B) is the abelian group of R-linear maps from A to B; this is an R-module if R is commutative.) This is a left exact functor from R-Mod to the category of abelian groups 𝐀𝐛, and so it has right derived functors RiT. The Ext groups are the abelian groups defined by

ExtRi(A,B)=(RiT)(B),

for an integer i. By definition, this means: take any injective resolution

0BI0I1,

remove the term B, and form the cochain complex:

0HomR(A,I0)HomR(A,I1).

For each integer i, ExtRi(A,B) is the cohomology of this complex at position i. It is zero for i negative. For example, ExtR0(A,B) is the kernel of the map HomR(A,I0)HomR(A,I1), which is isomorphic to HomR(A,B).

An alternative definition uses the functor G(A)=HomR(A,B), for a fixed R-module B. This is a contravariant functor, which can be viewed as a left exact functor from the opposite category (R-Mod)op to 𝐀𝐛. The Ext groups are defined as the right derived functors RiG:

ExtRi(A,B)=(RiG)(A).

That is, choose any projective resolution

P1P0A0,

remove the term A, and form the cochain complex:

0HomR(P0,B)HomR(P1,B).

Then ExtRi(A,B) is the cohomology of this complex at position i.

One may wonder why the choice of resolution has been left vague so far. In fact, Cartan and Eilenberg showed that these constructions are independent of the choice of projective or injective resolution, and that both constructions yield the same Ext groups.[4] Moreover, for a fixed ring R, Ext is a functor in each variable (contravariant in A, covariant in B).

For a commutative ring R and R-modules A and B, Exti
R
(A, B) is an R-module (using that HomR(A, B) is an R-module in this case). For a non-commutative ring R, Exti
R
(A, B) is only an abelian group, in general. If R is an algebra over a ring S (which means in particular that S is commutative), then Exti
R
(A, B) is at least an S-module.

Properties of Ext

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Here are some of the basic properties and computations of Ext groups.[5]

  • Ext0
    R
    (A, B) ≅ HomR(A, B) for any R-modules A and B.
  • Exti
    R
    (A, B) = 0 for all i > 0 if the R-module A is projective (for example, free) or if B is injective.
  • The converses also hold:
    • If Ext1
      R
      (A, B) = 0 for all B, then A is projective (and hence Exti
      R
      (A, B) = 0 for all i > 0).
    • If Ext1
      R
      (A, B) = 0 for all A, then B is injective (and hence Exti
      R
      (A, B) = 0 for all i > 0).
  • Exti(A,B)=0 for all i2 and all abelian groups A and B.[6]
  • Generalizing the previous example, ExtRi(A,B)=0 for all i2 if R is a principal ideal domain.
  • If R is a commutative ring and u in R is not a zero divisor, then
ExtRi(R/(u),B){B[u]i=0B/uBi=10otherwise,
for any R-module B. Here B[u] denotes the u-torsion subgroup of B, {xB:ux=0}. Taking R to be the ring of integers, this calculation can be used to compute Ext1(A,B) for any finitely generated abelian group A.
  • Generalizing the previous example, one can compute Ext groups when the first module is the quotient of a commutative ring by any regular sequence, using the Koszul complex.[7] For example, if R is the polynomial ring k[x1,...,xn] over a field k, then Ext*
    R
    (k,k) is the exterior algebra S over k on n generators in Ext1. Moreover, Ext*
    S
    (k,k) is the polynomial ring R; this is an example of Koszul duality.
  • By the general properties of derived functors, there are two basic exact sequences for Ext.[8] First, a short exact sequence 0KLM0 of R-modules induces a long exact sequence of the form
0HomR(A,K)HomR(A,L)HomR(A,M)ExtR1(A,K)ExtR1(A,L),
for any R-module A. Also, a short exact sequence 0KLM0 induces a long exact sequence of the form
0HomR(M,B)HomR(L,B)HomR(K,B)ExtR1(M,B)ExtR1(L,B),
for any R-module B.
  • Ext takes direct sums (possibly infinite) in the first variable and products in the second variable to products.[9] That is:
ExtRi(αMα,N)αExtRi(Mα,N)ExtRi(M,αNα)αExtRi(M,Nα)
S1ExtRi(A,B)ExtS1Ri(S1A,S1B).

Ext and extensions

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Equivalence of extensions

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The Ext groups derive their name from their relation to extensions of modules. Given R-modules A and B, an extension of A by B is a short exact sequence of R-modules

0BEA0.

Two extensions

0BEA0
0BEA0

are said to be equivalent (as extensions of A by B) if there is a commutative diagram:

Note that the Five lemma implies that the middle arrow is an isomorphism. An extension of A by B is called split if it is equivalent to the trivial extension

0BABA0.

There is a one-to-one correspondence between equivalence classes of extensions of A by B and elements of Ext1
R
(A, B).[11] This can be made precise as follows.

Proof. Fix a short exact sequence

0MPA0

where P is projective. Applying Hom(,B) yields the long exact sequence

Hom(P,B)Hom(M,B)δExt(A,B)0.

Given xExt(A,B), choose βHom(M,B) such that δ(β)=x. Consider the pushout of j:MP along β, given by the cokernel of the map

MPB,m(j(m),β(m)).

Define X as this pushout object. This yields the commutative diagram:

Here, XA is induced by the map PA. The bottom row is an extension of A by B, denoted ξ, and the connecting map δ ensures that δ(ξ)=x, proving surjectivity.

To show well-definedness on equivalence classes, suppose β is another lift of x. Then there exists fHom(P,B) such that β=β+fj. If X is the pushout of j and β, then an isomorphism XX is induced, making the extensions equivalent.

Conversely, given an extension

0BXA0,

the lifting property of P gives a map τ:PX fitting into the diagram

Here X is the pushout of j and γ. This shows that the map is injective.

Thus, the set of equivalence classes of extensions of A by B is naturally isomorphic to Ext(A,B). ∎

The trivial extension corresponds to the zero element of Ext1
R
(A, B).

The Baer sum of extensions

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The Baer sum is an explicit description of the abelian group structure on ExtR1(A,B), viewed as the set of equivalence classes of extensions of A by B.[12] Namely, given two extensions

0BfEgA0

and

0BfEgA0,

first form the pullback over A,

Γ={(e,e)EE|g(e)=g(e)}.

Then form the quotient module

Y=Γ/{(f(b),f(b))|bB}.

The Baer sum of E and E is the extension

0BYA0,

where the first map is b[(f(b),0)]=[(0,f(b))] and the second is (e,e)g(e)=g(e).

Up to equivalence of extensions, the Baer sum is commutative and has the trivial extension as identity element. The negative of an extension 0BEA0 is the extension involving the same module E, but with the homomorphism BE replaced by its negative.

Construction of Ext in abelian categories

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Nobuo Yoneda defined the abelian groups Extn
C
(A, B) for objects A and B in any abelian category C; this agrees with the definition in terms of resolutions if C has enough projectives or enough injectives. First, Ext0
C
(A,B) = HomC(A, B). Next, Ext1
C
(A, B) is the set of equivalence classes of extensions of A by B, forming an abelian group under the Baer sum. Finally, the higher Ext groups Extn
C
(A, B) are defined as equivalence classes of n-extensions, which are exact sequences

0BXnX1A0,

under the equivalence relation generated by the relation that identifies two extensions

ξ:0BXnX1A0ξ:0BX'nX'1A0

if there are maps XmX'm for all m in {1, 2, ..., n} so that every resulting square commutes 0BXnX1A0ιnι10BX'nX'1A0 that is, if there is a chain map ι:ξξ which is the identity on A and B.

The Baer sum of two n-extensions as above is formed by letting X'1 be the pullback of X1 and X'1 over A, and X'n be the pushout of Xn and X'n under B.[13] Then the Baer sum of the extensions is

0BX'nXn1X'n1X2X'2X'1A0.

The derived category and the Yoneda product

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An important point is that Ext groups in an abelian category C can be viewed as sets of morphisms in a category associated to C, the derived category D(C).[14] The objects of the derived category are complexes of objects in C. Specifically, one has

Ext𝐂i(A,B)=HomD(𝐂)(A,B[i]),

where an object of C is viewed as a complex concentrated in degree zero, and [i] means shifting a complex i steps to the left. From this interpretation, there is a bilinear map, sometimes called the Yoneda product:

Ext𝐂i(A,B)×Ext𝐂j(B,C)Ext𝐂i+j(A,C),

which is simply the composition of morphisms in the derived category.

The Yoneda product can also be described in more elementary terms. For i = j = 0, the product is the composition of maps in the category C. In general, the product can be defined by splicing together two Yoneda extensions.

Alternatively, the Yoneda product can be defined in terms of resolutions. (This is close to the definition of the derived category.) For example, let R be a ring, with R-modules A, B, C, and let P, Q, and T be projective resolutions of A, B, C. Then Exti
R
(A,B) can be identified with the group of chain homotopy classes of chain maps PQ[i]. The Yoneda product is given by composing chain maps:

PQ[i]T[i+j].

By any of these interpretations, the Yoneda product is associative. As a result, ExtR*(A,A) is a graded ring, for any R-module A. For example, this gives the ring structure on group cohomology H*(G,), since this can be viewed as Ext[G]*(,). Also by associativity of the Yoneda product: for any R-modules A and B, ExtR*(A,B) is a module over ExtR*(A,A).

Important special cases

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where G is a group, M is a representation of G over the integers, and [G] is the group ring of G.
  • For a sheaf of modules on a ringed space (X,𝒪X), taking the right derived functors of the sheaf Hom 𝓂X(,), the internal Hom in the category of 𝒪X-modules, gives the Ext sheaves 𝓍𝓉X*(,).[15] They are related to the global Ext groups via the local-to-global Ext spectral sequence.
  • For a commutative Noetherian local ring R with residue field k, ExtR*(k,k) is the universal enveloping algebra of a graded Lie algebra π*(R) over k, known as the homotopy Lie algebra of R. (To be precise, when k has characteristic 2, π*(R) has to be viewed as an "adjusted Lie algebra".[16]) There is a natural homomorphism of graded Lie algebras from the André–Quillen cohomology D*(k/R,k) to π*(R), which is an isomorphism if k has characteristic zero.[17]

See also

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Notes

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  1. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  2. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  3. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  4. ^ Weibel (1994), sections 2.4 and 2.5 and Theorem 2.7.6.
  5. ^ Weibel (1994), Chapters 2 and 3.
  6. ^ Weibeil (1994), Lemma 3.3.1.
  7. ^ Weibel (1994), section 4.5.
  8. ^ Weibel (1994), Definition 2.1.1.
  9. ^ Weibel (1994), Proposition 3.3.4.
  10. ^ Weibel (1994), Proposition 3.3.10.
  11. ^ Weibel (1994), Theorem 3.4.3.
  12. ^ Weibel (1994), Corollary 3.4.5.
  13. ^ Weibel (1994), Vists 3.4.6. Some minor corrections are in the errata.
  14. ^ Weibel (1994), sections 10.4 and 10.7; Gelfand & Manin (2003), Chapter III.
  15. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value)., §III.6
  16. ^ Sjödin (1980), Notation 14.
  17. ^ Avramov (2010), section 10.2.

References

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  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).