1956 Wimbledon Championships

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1956 Wimbledon Championships
Date25 June – 7 July
Edition70th
CategoryGrand Slam
SurfaceGrass
LocationChurch Road
SW19, Wimbledon,
London, United Kingdom
VenueAll England Lawn Tennis and Croquet Club
Attendance276,861
Champions
Men's singles
Australia Lew Hoad
Women's singles
United States Shirley Fry
Men's doubles
Australia Lew Hoad / Australia Ken Rosewall
Women's doubles
United Kingdom Angela Buxton / United States Althea Gibson
Mixed doubles
United States Vic Seixas / United States Shirley Fry
Boys' singles
United States Ronnie Holmberg
Girls' singles
United Kingdom Ann Haydon
← 1955 ·
· 1957 →

The 1956 Wimbledon Championships took place on the outdoor grass courts at the All England Lawn Tennis and Croquet Club in Wimbledon, London, United Kingdom. The tournament was held from Monday 25 June until Saturday 7 July 1956.[1] It was the 70th staging of the Wimbledon Championships, and the third Grand Slam tennis event of 1956. Lew Hoad and Shirley Fry won the singles titles.

Champions

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Seniors

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Men's singles

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Australia Lew Hoad defeated Australia Ken Rosewall, 6–2, 4–6, 7–5, 6–4 [2]

Women's singles

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United States Shirley Fry defeated United Kingdom Angela Buxton, 6–3, 6–1 [3]

Men's doubles

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Australia Lew Hoad / Australia Ken Rosewall defeated Italy Nicola Pietrangeli / Italy Orlando Sirola, 7–5, 6–2, 6–1 [4]

Women's doubles

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United Kingdom Angela Buxton / United States Althea Gibson defeated Australia Fay Muller / Australia Daphne Seeney, 6–1, 8–6 [5]

Mixed doubles

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United States Vic Seixas / United States Shirley Fry defeated United States Gardnar Mulloy / United States Althea Gibson, 2–6, 6–2, 7–5 [6]

Juniors

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Boys' singles

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United States Ronnie Holmberg defeated Australia Rod Laver, 6–1, 6–1 [7]

Girls' singles

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United Kingdom Ann Haydon defeated West Germany Ilse Buding, 6–3, 6–4 [8]

References

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