Lieb–Liniger model

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In physics, the Lieb–Liniger model describes a gas of particles moving in one dimension and satisfying Bose–Einstein statistics. More specifically, it describes a one dimensional Bose gas with Dirac delta interactions. It is named after Elliott H. Lieb and Werner Liniger (de) who introduced the model in 1963.[1] The model was developed to compare and test Nikolay Bogolyubov's theory of a weakly interacting Bose gas.[2]

Definition

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Given N bosons moving in one-dimension on the x-axis defined from [0,L] with periodic boundary conditions, a state of the N-body system must be described by a many-body wave function ψ(x1,x2,,xj,,xN). The Hamiltonian, of this model is introduced as

H=i=1N2xi2+2ci=1Nj>iNδ(xixj) ,

where δ is the Dirac delta function. The constant c denotes the strength of the interaction, c>0 represents a repulsive interaction and c<0 an attractive interaction.[3] The hard core limit c is known as the Tonks–Girardeau gas.[3]

For a collection of bosons, the wave function is unchanged under permutation of any two particles (permutation symmetry), i.e., ψ(,xi,,xj,)=ψ(,xj,,xi,) for all ij and ψ satisfies ψ(,xj=0,)=ψ(,xj=L,) for all j.

The delta function in the Hamiltonian gives rise to a boundary condition when two coordinates, say x1 and x2 are equal. The condition is that as x2 approaches x1 from above (x2x1), the derivative satisfies

(x2x1)ψ(x1,x2)|x2=x1+=cψ(x1=x2).

Solution

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File:Lieb-liniger-1.gif
Fig. 1: The ground state energy (per particle) e as a function of the interaction strength per density γ=Lc/N, from.[1]

The time-independent Schrödinger equation

Hψ=Eψ

, is solved by explicit construction of

ψ

. Since

ψ

is symmetric it is completely determined by its values in the simplex

, defined by the condition that

0x1x2,xNL

.

The solution can be written in the form of a Bethe ansatz as[2]

ψ(x1,,xN)=Pa(P)exp(ij=1NkPjxj),

with wave vectors 0k1k2,kN, where the sum is over all N! permutations, P, of the integers 1,2,,N, and P maps 1,2,,N to P1,P2,,PN. The coefficients a(P), as well as the k's are determined by the condition Hψ=Eψ, and this leads to a total energy

E=j=1Nkj2,

with the amplitudes given by

a(P)=1i<jN(1+ickPikPj).[4]

These equations determine ψ in terms of the k's. These lead to N equations:[2]

Lkj=2πIj 2i=1Narctan(kjkic)for j=1,,N ,

where I1<I2<<IN are integers when N is odd and, when N is even, they take values ±12,±32, . For the ground state the I's satisfy

Ij+1Ij=1,for 1j<Nand I1=IN.

Thermodynamic limit

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References

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  1. ^ a b Elliott H. Lieb and Werner Liniger, Exact Analysis of an Interacting Bose Gas. I. The General Solution and the Ground State, Physical Review 130: 1605–1616, 1963
  2. ^ a b c Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  3. ^ a b Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  4. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).