Dimension of a scheme

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In algebraic geometry, the dimension of a scheme is a generalization of the dimension of an algebraic variety. Scheme theory emphasizes the relative point of view and, accordingly, the relative dimension of a morphism of schemes is also important.

Definition

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By definition, the dimension of a scheme X is the dimension of the underlying topological space: the supremum of the lengths of chains of irreducible closed subsets:

V0V1VX.[1]

In particular, if X=SpecA is an affine scheme, then such chains correspond to chains of prime ideals (inclusion reversed), so the dimension of X is precisely the Krull dimension of A.

If Y is an irreducible closed subset of a scheme X, then the codimension of Y in X is the supremum of the lengths of chains of irreducible closed subsets:

Y=V0V1VX.[2]

An irreducible subset of X is an irreducible component of X if and only if its codimension in X is zero. If X=SpecA is affine, then the codimension of Y in X is precisely the height of the prime ideal defining Y in X.

Examples

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  • If a finite-dimensional vector space V over a field is viewed as a scheme over the field,[note 1] then the dimension of the scheme V is the same as the vector-space dimension of V.
  • Let X=Speck[x,y,z]/(xy,xz), k a field. Then it has dimension 2 (since it contains the hyperplane H={x=0}𝔸3 as an irreducible component). If x is a closed point of X, then codim(x,X) is 2 if x lies in H and is 1 if it is in XH. Thus, codim(x,X) for closed points x can vary.
  • Let X be an algebraic pre-variety; i.e., an integral scheme of finite type over a field k. Then the dimension of X is the transcendence degree of the function field k(X) of X over k.[3] Also, if U is a nonempty open subset of X, then dimU=dimX.[4]
  • Let R be a discrete valuation ring and X=𝔸R1=Spec(R[t]) the affine line over it. Let π:XSpecR be the projection. Spec(R)={s,η} consists of 2 points, s corresponding to the maximal ideal and closed and η the zero ideal and open. Then the fibers π1(s),π1(η) are closed and open, respectively. We note that π1(η) has dimension one,[note 2] while X has dimension 2=1+dimR and π1(η) is dense in X. Thus, the dimension of the closure of an open subset can be strictly bigger than that of the open set.
  • Continuing the same example, let 𝔪R be the maximal ideal of R and ωR a generator. We note that R[t] has height-two and height-one maximal ideals; namely, 𝔭1=(ωRt1) and 𝔭2= the kernel of R[t]R/𝔪R,ff(0)mod𝔪R. The first ideal 𝔭1 is maximal since R[t]/(ωRt1)=R[ωR1]= the field of fractions of R. Also, 𝔭1 has height one by Krull's principal ideal theorem and 𝔭2 has height two since 𝔪R[t]𝔭2. Consequently,
codim(𝔭1,X)=1,codim(𝔭2,X)=2,
while X is irreducible.

Equidimensional scheme

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An equidimensional scheme (or, pure dimensional scheme) is a scheme whose irreducible components are of the same dimension (implicitly assuming the dimensions are all well-defined).

Examples

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All irreducible schemes are equidimensional.[5]

In an affine space, the union of a line and a point not on the line is not equidimensional. Generally, if two closed subschemes of some scheme, neither containing the other, have unequal dimensions, then their union is not equidimensional.

If a scheme is smooth (for instance, étale) over Spec k for some field k, then every connected component (which is then, in fact, an irreducible component) is equidimensional.

Relative dimension

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Let f:XY be a morphism locally of finite type between two schemes X and Y. The relative dimension of f at a point yY is the dimension of the fiber f1(y). If all the nonempty fibers [clarification needed] are purely of the same dimension n, then one says that f is of relative dimension n.[6]

See also

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Notes

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  1. ^ The Spec of the symmetric algebra of the dual vector space of V is the scheme structure on V.
  2. ^ In fact, by definition, π1(η) is the fiber product of π:XSpec(R) and η=Spec(k(η))SpecR and so it is the Spec of R[t]Rk(η)=k(η)[t].
  1. ^ Hartshorne 1977, Ch. I, just after Corollary 1.6.
  2. ^ Hartshorne 1977, Ch. II, just after Example 3.2.6.
  3. ^ Hartshorne 1977, Ch. II, Exercise 3.20. (b)
  4. ^ Hartshorne 1977, Ch. II, Exercise 3.20. (e)
  5. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value)..
  6. ^ Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).

References

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  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
[edit | edit source]
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).
  • Lua error in Module:Citation/CS1/Configuration at line 2172: attempt to index field '?' (a nil value).